Chapter III

Voltage Drop & Conductor Adjustments

JourneymanPractice study guide with diagrams.

Voltage Drop & Conductor Adjustments

Learning Objectives

By the end of this chapter, you should be able to:

4.Explain the difference between a recommendation and a requirement for voltage drop in the NEC.
5.Calculate voltage drop for both single-phase and three-phase systems using the standard formula.
6.Identify when conductor ampacity must be adjusted for ambient temperature and when it must be corrected for more than three current-carrying conductors in a raceway or cable.
7.Apply the correct adjustment and correction factors from the appropriate tables.
8.Determine the minimum conductor size after applying adjustments and corrections, ensuring it still meets the overcurrent protection requirements of 240.4.
9.Navigate the NEC quickly to find the relevant tables and sections for these calculations.

1.1 The Fundamental Difference: Ampacity vs. Voltage Drop

Before diving into calculations, you must understand two distinct but related concepts.

Ampacity is the current a conductor can carry continuously under the conditions of use without exceeding its temperature rating. This is a safety issue. The NEC mandates that conductors be protected against excessive current (Article 240) and that their ampacity be sufficient for the connected load (Article 210, 215, 230, etc.). Ampacity is determined by the conductor's material, size, insulation temperature rating, and the environment it is installed in (ambient temperature, number of conductors, etc.).

Voltage Drop is the reduction in voltage in an electrical circuit between the source and the load. This is primarily a performance issue. Excessive voltage drop can cause motors to overheat, lights to dim, and electronic equipment to malfunction. The NEC contains informational notes (formerly fine print notes) that recommend limiting voltage drop to 3% for a branch circuit or feeder and a total of 5% for the combined feeder and branch circuit. Crucially, these are recommendations, not mandatory requirements. The only mandatory voltage drop requirements in the NEC are for specific systems, such as fire alarm circuits (760.45) and some specialized systems.

Practical Field Point: A journeyman must know the difference. A customer may request a voltage drop calculation, but the inspector will only fail an installation for a violation of a mandatory rule, not a recommendation. However, a good journeyman will always design for the recommended values to ensure proper equipment operation.


1.2 Voltage Drop Calculations

The NEC does not provide a single mandatory calculation method. The most common and practical method for the field is the approximate formula using the conductor's effective impedance (Z). For most calculations, resistance (R) is used, as reactance is negligible for smaller conductors and lower voltages.

The Standard Formula:

For single-phase systems:

VD = (2 × K × I × L) / Cmils

For three-phase systems:

VD = (1.732 × K × I × L) / Cmils

Where:

VD = Voltage Drop (in volts)
K = Direct current resistance constant. A common value is 12.9 for copper and 21.2 for aluminum. These are based on the resistance of a 1,000-cmil conductor that is 1,000 feet long at 75°C.
I = Current (in amperes)
L = One-way length of the conductor run (in feet)
Cmils = Cross-sectional area of the conductor in circular mils (found in NEC Chapter 9, Table 8)

Example: A 240-volt, single-phase branch circuit supplies a 24-amp load located 150 feet from the panel. The conductor is 10 AWG copper (10,380 Cmils). What is the voltage drop?

VD = (2 × 12.9 × 24 × 150) / 10,380

VD = 92,880 / 10,380

VD = 8.95 volts

To find the percentage drop: (8.95V / 240V) × 100 = 3.7%. This exceeds the 3% recommendation.

Exam Trap: Many candidates forget to use the one-way length. The "2" in the single-phase formula accounts for the total circuit length (out and back). The "1.732" in the three-phase formula accounts for the phase-to-phase relationship. Do not double-count the length.


1.3 Conductor Ampacity Adjustments and Corrections

This is where the NEC becomes a true codebook. The base ampacity of a conductor is found in the ampacity tables of Article 310 (specifically Table 310.16 for the most common installations). However, this base rating is only valid for a specific set of conditions:

Not more than three current-carrying conductors in a raceway or cable.
An ambient temperature of 30°C (86°F).
The conductor's insulation temperature rating (60°C, 75°C, or 90°C).

When these conditions change, you must adjust the ampacity.

1.3.1 Ambient Temperature Correction (Table 310.16, Correction Factors)

If the ambient temperature where the conductor is installed is higher than 30°C, the conductor cannot dissipate heat as effectively, so its ampacity must be reduced. You apply the correction factor from the bottom of Table 310.16.

Find the column for the conductor's insulation temperature rating (e.g., 75°C).
Find the row for the actual ambient temperature.
Multiply the base ampacity by the correction factor.

Example: A 3 AWG copper conductor with 75°C insulation has a base ampacity of 100 amps. If installed in an area with an ambient temperature of 45°C, the correction factor is 0.82. The corrected ampacity is 100 × 0.82 = 82 amps.

Practical Field Point: This is common for rooftop installations in Texas. The ambient temperature on a roof can be significantly higher than the surrounding air temperature. The NEC requires an additional temperature adder of 33°C (60°F) to the ambient temperature for conductors installed within a certain distance of a rooftop (310.15(B)(3)(c)). This is a critical factor for solar and HVAC installations.

1.3.2 Adjustment for More Than Three Current-Carrying Conductors (Table 310.15(B)(3)(a))

When more than three current-carrying conductors are bundled together in a raceway or cable, their ability to dissipate heat is reduced. The NEC requires you to apply an adjustment factor from Table 310.15(B)(3)(a).

Find the row for the number of current-carrying conductors (4-6, 7-9, 10-20, etc.).
Multiply the base ampacity by the adjustment factor.

Example: Four 12 AWG THHN (90°C) conductors are installed in a single conduit. The base ampacity from the 90°C column is 30 amps. The adjustment factor for 4-6 conductors is 0.80. The adjusted ampacity is 30 × 0.80 = 24 amps.

Important Note: The neutral conductor is not counted as a current-carrying conductor if it only carries the unbalanced current of a multiwire branch circuit (310.15(E)(1)). However, in a circuit where the neutral carries the full load (e.g., a 120V, 2-wire circuit), it is counted.


1.4 The Order of Operations and Terminal Temperature Limits

This is the most common source of errors on the exam. You must apply the adjustments and corrections in the correct order and then check the final result against the termination temperature limits.

The Process:

60.Determine the base ampacity from Table 310.16, using the 90°C column if the conductor has a 90°C insulation rating (like THHN or XHHW-2). This is the starting point for all calculations.
61.Apply the adjustment and correction factors to the 90°C ampacity. Multiply the base ampacity by the ambient temperature correction factor and the conductor bundling adjustment factor. This gives you the adjusted ampacity.
62.Check the termination temperature limits. The terminals of most standard equipment (breakers, panels, lugs) are rated at 60°C or 75°C. The NEC (110.14(C)) limits the ampacity of the conductor to the ampacity of the terminal rating. This means you cannot use the 90°C ampacity for the final ampacity of the conductor if the terminals are only rated for 75°C.

The Rule: The final ampacity of the conductor is the lower of the following:

The adjusted/corrected ampacity from Step 2.
The ampacity from the 60°C or 75°C column of Table 310.16 (based on the terminal rating).

Example: A 1 AWG THHN (90°C) copper conductor is installed with three other current-carrying conductors in a conduit (4 total) in a 40°C ambient environment. The terminals are rated at 75°C.

67.Base ampacity (90°C column): 130 amps.
68.Adjustment (4-6 conductors): 0.80. Correction (40°C): 0.91. Adjusted ampacity = 130 × 0.80 × 0.91 = 94.6 amps.
69.Terminal limit (75°C column): 110 amps.

The final ampacity is the lower of the two, which is 94.6 amps. You must use the 90°C column for the adjustments, but you cannot exceed the 75°C terminal rating.

Exam Trap: A common trick is to ask for the maximum load a conductor can supply. You must always check the terminal rating. If you only calculate the adjusted ampacity (94.6 amps) and ignore the terminal limit (110 amps), you would incorrectly state the maximum load is 94.6 amps. In this case, the adjusted ampacity is lower, so it is the limiting factor. But if the adjusted ampacity had been 120 amps, the terminal limit of 110 amps would be the limiting factor.


1.5 Conductor Sizing for a Specific Load

When you need to size a conductor for a specific load, you work the process in reverse.

75.Determine the load current (e.g., 75 amps).
76.Divide the load current by the adjustment and correction factors to find the minimum required ampacity before adjustments.
Required Ampacity = Load / (Adjustment Factor × Correction Factor)
78.Select a conductor from the 90°C column of Table 310.16 that has an ampacity equal to or greater than the value from Step 2.
79.Check the terminal temperature limit. The conductor's ampacity from the 60°C or 75°C column must be equal to or greater than the load current.

Example: A 75-amp load is to be supplied by a THHN (90°C) copper conductor. The conductor will be run with three other current-carrying conductors (4 total) in an ambient temperature of 40°C. The terminals are rated at 75°C.

81.Load = 75 amps.
82.Required Ampacity = 75 / (0.80 × 0.91) = 75 / 0.728 = 103 amps.
83.From the 90°C column of Table 310.16, a 2 AWG copper conductor has an ampacity of 115 amps. This is the minimum size that meets the adjusted ampacity requirement.
84.Check the 75°C terminal limit: A 2 AWG conductor has an ampacity of 95 amps in the 75°C column. Since 95 amps ≥ 75 amps, this is acceptable.

Final Conductor Size: 2 AWG copper.


1.6 Overcurrent Protection and the "Next Size Up" Rule

After sizing the conductor, you must select the overcurrent protection device (breaker or fuse). The general rule is that the breaker must protect the conductor. However, 240.4(B) allows you to use the next standard size up if the conductor ampacity does not correspond to a standard rating.

The Rule: If the conductor's ampacity is not a standard rating, you can use the next higher standard overcurrent device rating, provided that:

The conductor ampacity is not less than the load.
The next higher standard rating does not exceed 800 amps.

Example: A conductor has an ampacity of 94.6 amps (from our earlier example). The next standard size up is 100 amps. You can use a 100-amp breaker.

Exam Trap: This rule applies to the ampacity of the conductor, not the calculated load. If the load is 95 amps, you cannot use a 100-amp breaker if the conductor's ampacity is only 94.6 amps. The conductor's ampacity must be at least 95 amps to protect the conductor. You would need to increase the conductor size.


Code Navigation

This is your roadmap for the open-book exam. Know these locations.

ConceptNEC Location
**Voltage Drop (Recommendations)**NEC 210.19(A) Informational Note No. 4 (Branch Circuits); NEC 215.2(A)(1) Informational Note No. 2 (Feeders)
**Conductor Properties (Cmils, Resistance)**NEC Chapter 9, Table 8
**Ampacity Tables**NEC Table 310.16 (60°C/75°C/90°C)
**Ambient Temperature Correction Factors**NEC Table 310.16, Bottom Portion
**Adjustment for >3 Current-Carrying Conductors**NEC Table 310.15(B)(3)(a)
**Rooftop Temperature Adders**NEC 310.15(B)(3)(c)
**Neutral Conductor as Current-Carrying**NEC 310.15(E)(1)
**Termination Temperature Limits**NEC 110.14(C)
**Overcurrent Protection (Next Size Up)**NEC 240.4(B)
**Standard Overcurrent Device Ratings**NEC 240.6(A)

Common Exam Traps Summary

100.Voltage Drop is a Recommendation: Do not treat it as a hard requirement unless a specific section mandates it.
101.Use the 90°C Column for Adjustments: Always start with the 90°C ampacity if the insulation is rated for it.
102.Check the Terminals: The final ampacity can never exceed the terminal temperature rating (60°C or 75°C).
103.Order of Operations: Adjustments and corrections are applied to the 90°C ampacity. The terminal limit is checked separately.
104.Neutral Counting: The neutral is not counted if it only carries unbalanced current in a multiwire circuit.
105.Rooftop Heat: Remember the 33°C adder for rooftop conductor installations.
106.Next Size Up: The "next size up" rule in 240.4(B) is based on the conductor's ampacity, not the load.
107.Units: Always use one-way length for voltage drop calculations. The "2" or "1.732" accounts for the return path or phase relationship.

Ready to test this chapter?

Practice with exam-aligned questions and timed simulations.

Start Practicing Free